Tentukan penyelesaian dari sistem persamaan berikut 1/x+2 + 1/y+1 = 6 dan 2/x+2 + 1/2y+2 = 4 /=per Bantu jawab secepatnya ya:) besok dikumpulin soalnya

[tex] \frac{1}{x + 2} + \frac{1}{y + 1} = 6 ..........(1)\\ \frac{2}{x + 2} + \frac{1}{2y + 2} = 4.........(2)[/tex]
Kalikan 2 persamaan (1), kemudian kurangkan dengan persamaan (2), sehingga:
[tex] \frac{2}{x + 2} + \frac{2}{y + 1} = 6\\ \frac{2}{x + 2} + \frac{1}{2y + 2} = 4 \\ \frac{2}{y + 1} - \frac{1}{2(y + 1)} = 2 \\ \frac{4 - 1}{2(y + 1)} = 2 \\ \frac{3}{y + 1} = 4 \\ 3 = 4y + 4 \\ 4y = - 1 \\ y = - \frac{1}{4} [/tex]
subtitusi kan y ke persamaan (1), sehingga:
[tex] \frac{1}{x + 2} + \frac{1}{y + 1} = 6 \\ \frac{1}{x + 2} + \frac{1}{ - \frac{1}{4} + 1} = 6 \\ \frac{1}{x + 2} + \frac{1}{ \frac{3}{4} } = 6 \\ \frac{1}{x + 2} + \frac{4}{3} = 6 \\ \frac{1}{x + 2} = 6 - \frac{4}{3} \\ \frac{1}{x + 2} = \frac{14}{3} \\ 3 = 14x + 28 \\ 14x = - 25 \\ x = - \frac{25}{14} [/tex]
jadi himpunan penyelesaian:
[tex] \{- \frac{25}{14}, - \frac{1}{4} \}[/tex]