Tentukan persamaan garis melalui titik (3,-4) dan (-7,-2) Makasiii yg udah jawaabbbb:))

y-y1/y2-y1 = x-x1/x2-x1
y-(-4)4/(-2)-(-4) = x-3/(-7)-3
y+4/(-2)+4 = x-3/(-7)-3
y+4/2 = x-3/(-10)
(-10)(y+4) = 2(x-3)
-10y-40 = 2x-6
-10y-2x-40-6 = 0
-10y-2x-46 = 0
2x+10y+46 = 0
x+5y+23 = 0