Matematika

Pertanyaan

Integral dari (2x - 1/x)^2 dx

1 Jawaban

  • = int (2x - 1/x)^2 dx
    = int (4x^2 - 4 + 1/x^2) dx
    = int (4x^2 - 4 + x^-2) dx
    = 4/(2+1) x^(2+1) - 4x + 1/(-2+1) x^(-2+1) + C
    = 4/3 x^3 - 4x + 1/-1 x^-1 +C
    = 4/3 x^3 - 4x - x^-1 + C
    = 4/3 x^3 - 4x - 1/x + C

    *semoga membantu

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