alog 243=5 7log = 0 maka nilai 4a -2b adalah

[tex] ^{a} log(243) = 5 \\ ^{7} log(b) = 0 \\ {a}^{5} = 243 \\ {7}^{0} = b \\ a = \sqrt[5]{243} = 3 \\ b = 1 \\ 4a - 2b = 4(3) - 2(1) = 12 - 2 = 10[/tex]

semoga membantu:)