5 a.tentukan garis 4 ×=3y dan melalui titik (3,2) b.garis y =2per3×+1danelalui titik (-1,4) bnatu kakak mau dikumpulin skarang nihhhh

a) 4x=3y » y=4/3 x
m = 4/3
melalui (3,2)
y-y1=m(x-x1)
y-2= 4/3(x-3)
y-2= 4/3x - 4
y= 4/3x - 4+2
y= 4/3x -2
y = 4/3x - 6/3
3y - 4x +6 = 0

b) y = ⅔x +1 melalui (-1,4)
m = ⅔
y-4= ⅔(x + 1)
y-4= ⅔x +⅔
y= ⅔x + ⅔ + 12/3
y = ⅔x + 14/3
3y -2x -14 =0