Matematika

Pertanyaan

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tolong bantuuu yaaa plisss

2 Jawaban

  • 2a) p²q (2/p ÷ q)
    = p²q (2/p × 1/q)
    = (p²q)(2)
    ----------------
    (pq)
    = 2p²q
    -----------
    pq
    = (pq)(2p)
    ---------------
    (pq)
    = 2p

    b)(ab)³(a + b)
    = a³b³(a + b)
    = a⁴b³ + a³b⁴

    3) 3^x+2 = 1 / 27 ^x-2
    3^x+2 = (3-³)^x-2
    => x + 2 = - 3x + 6
    => x + 3x = 6 - 2
    => 4x = 4
    => x = 1
    hp = {1}

    4) (½)^-2x-2 = 2⁴
    => (2-¹)^-2x - 2 = 2⁴
    => 2x + 2 = 4
    => 2x = 4 - 2
    => 2x = 2
    => x = 1
    hp = {1}
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