Ujian Nasional

Pertanyaan

pH larutan 100 ml CH3COONa 0,1 M adalah... (Ka CH3COOH=10-5,Kw=10-14)
pH larutan 100 ml CH3COONa 0,1 M adalah... (Ka CH3COOH=10-5,Kw=10-14)

1 Jawaban

  • Mol CH3COONa = 100 ml x 0,1 mmol/ml = 10 mmol
    Mol ion [Na+] = 1 x 10 = 10 mmol

    [OH-] = kb x b/g
    = 1 x 10-5 (10/10)
    = 1 x 10-5 = 1 x 10-6
    POH = -log 1 x 10-6
    = 6 - log 1
    Maka pH = 14 - (6 - log 1)
    = 8