tentukan persamaan kuadrat yang akar - akarnya -2 dan,-3

akar-akarnya -2 dan -3
berarti
x = - 2 ---> x + 2 = 0
x = - 3 ---> x + 3 = 0

(x + 2) . (x + 3) = [tex] x^{2} [/tex] + 2x + 3x + 6 = [tex] x^{2} [/tex] + 5x + 6

x1 = -2
x2 = -3

(x - x1)(x - x2) = 0
(x - (-2))(x - (-3)) = 0
(x + 2)(x + 3) = 0
x² + 2x + 3x + 6 = 0
x² + 5x + 6 = 0