Matematika

Pertanyaan

Tentukan hp pera log(2x-1)-log(x-3)=log7

2 Jawaban

  • log(2x-1)-log(x-3)=log7
    log (
    [tex] \frac{2x-1}{x-3} [/tex]) = log 7
    [tex] \frac{2x-1}{x-3} =7[/tex]
    7(x-3)=2x-1
    7x-21=2x-1
    5x=20
    x=4
  • Bab Logaritma
    Matematika SMA Kelas X

    log (2x - 1) - log (x - 3) = log 7
    log ((2x - 1) / (x - 3)) = log 7
    (2x - 1) / (x - 3) = 7
    2x - 1 = 7 (x - 3)
    2x - 1 = 7x - 21
    2x - 7x = -21 + 1
    -5x = -20
    x = -20 : (-5)
    x = 4

    HP = { 4 }

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