Tentukan hp pera log(2x-1)-log(x-3)=log7
Matematika
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Pertanyaan
Tentukan hp pera log(2x-1)-log(x-3)=log7
2 Jawaban
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1. Jawaban aw131719
log(2x-1)-log(x-3)=log7
log ([tex] \frac{2x-1}{x-3} [/tex]) = log 7
[tex] \frac{2x-1}{x-3} =7[/tex]
7(x-3)=2x-1
7x-21=2x-1
5x=20
x=4 -
2. Jawaban Anonyme
Bab Logaritma
Matematika SMA Kelas X
log (2x - 1) - log (x - 3) = log 7
log ((2x - 1) / (x - 3)) = log 7
(2x - 1) / (x - 3) = 7
2x - 1 = 7 (x - 3)
2x - 1 = 7x - 21
2x - 7x = -21 + 1
-5x = -20
x = -20 : (-5)
x = 4
HP = { 4 }