F(×)=X2+4×+5= G(×)=×-5= fog(×)= F(×)= G(×)= Gof(3)= Tolong jawab dengan cepat yahh!!
Matematika
hervanie
Pertanyaan
F(×)=X2+4×+5=
G(×)=×-5=
fog(×)=
F(×)=
G(×)=
Gof(3)=
Tolong jawab dengan cepat yahh!!
G(×)=×-5=
fog(×)=
F(×)=
G(×)=
Gof(3)=
Tolong jawab dengan cepat yahh!!
2 Jawaban
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1. Jawaban Riskaevita1
f(x) = x^2 + 4 + 5
g(x) = x - 5
Fog = F (g (x) )
Fog = (x-5)^2 + 4(x- 5 ) + 5
Fog = x^2 - 10x + 25 + 4x - 20 + 5
Fog = x^2 - 6x - 10
g o f (x)= g (f(x))
g o f (x)=(x^2 + 4x + 5 ) - 5
g o f (x)=x^2 + 4x
g o f (3) = 3^2 + 4(3)
g o f (3) = 9 + 12
g o f (3) = 21
SEMOGA MEMBANTU MAKASIH -
2. Jawaban BSunShine
Materi : Fungsi Komposisi
Kelas : X & XI SMA
f(x) = x^2 + 4x + 5
g(x) = x - 5
f o g (x) = f(g(x))
f o g (x) = (x - 5)^2 + 4(x - 5) + 5
f o g (x) = x^2 - 10x + 25 + 4x - 20 + 5
f o g (x) = x^2 - 6x - 10
g o f (x) = g(f(x))
g o f (x) = (x^2 + 4x + 5) - 5
g o f (x) = x^2 + 4x
jadi :
》g o f (3) = x^2 + 4x
》g o f (3) = (3)^2 + 4(3)
》g o f (3) = 9 + 12
》g o f (3) = 21
Semangat ^_^