Tentukan persamaan garis yang melalui titik (2,1)dan(3,5)

x1=2. x2=3
y1=1. y2=5

Rumus=y2-y1/x2-x1

5-1/3-2=4/1
=4

(2,1) dan (3,5)
x1 = 2
x2 = 3
y1 = 1
y2 = 5

[tex] \binom{y - y1 = x - x1}{y2 - y1 = x2 - x1} \\ \binom{y - 1 = x - 2}{5 - 1 = 3 -2} \\ \binom{y - 1 = x - 2}{4 = 1} \\ 1(y - 1) = 4(x - 2) \\ 1y - 1 = 4x - 8 \\ 1y - 4x - 1 + 8 = 0 \\ 1y - 4x + 7 = 0[/tex]
maaf kalo salah :)