Jika f(x)= 1/2x-6 maka f^-1(x)? ^=pangkat Mohon dibantu terima kasih

Misalkan [tex]f^{-1}(x) = t[/tex]
[tex]f^{-1}(x)=t \\ f(t) = x \\ \frac{1}{2}t - 6 = x \\ \frac{1}{2}t = x+6 \\ t =2(x+6) \\ \therefore t=2x+12[/tex],
Jadi, [tex]f^{-1}(x) = 2x+12[/tex]

[tex] f(x) = \frac{1}{2x - 6} \\ {inversnya} \\ x = \frac{1}{2.f^{-1}(x) - 6} \\ 2.f^{-1}(x) - 6 = \frac{1}{x} \\ 2.f^{-1}(x) = \frac{1}{x} + 6 \\ 2.f^{-1}(x) = \frac{1}{x} + \frac{6x}{x} \\ 2.f^{-1}(x) = \frac{6x + 1}{x} \\ f^{-1}(x) = \frac{6x + 1}{2x} [/tex]