tolong jawab ya, besok dikumpul, nomor 6 saja

[tex] \sqrt{ {9}^{5 - x} } = 27 \sqrt{ {3}^{ - x - 1} } \\ \sqrt{ ({3}^{2})^{5 - x} } = {3}^{3} \times 3 ^ {\frac{ - x - 1}{2} } \\ {3}^{ \frac{2(5 - x)}{2} } = {3}^{3 + \frac{ - x - 1}{2} } \\ \frac{2(5 - x)}{2} = 3 + \frac{ - x - 1}{2} \\ 5 - x = \frac{6 - x - 1}{2} \\ 10 - 2x = 5 - x \\ - x = - 5 \\ x = 5[/tex]

semoga membantu:)