1.invers dari (5 1 ) (8 2 ) 2. diterminan dari P= \left[\begin{array}{ccc}3&1&2\\1&0&-2\\-5&1&3\end{array}\right]

[tex]a. \star invers \left[\begin{array}{ccc}5&1\\8&2\end{array}\right] . Cari determinan dahulu =5.2-1.8 =2 Rumus invers: D^-1= \frac{1}{det A} \left[\begin{array}{ccc}5&1\\8&2\end{array}\right] . =\boxed { \frac{1}{2} \left[\begin{array}{ccc}5&1\\8&2\end{array}\right] }. = \left[\begin{array}{ccc} \frac{5}{2} & \frac{1}{2} \\ \frac{8}{2} & \frac{2}{2} \end{array}\right] . = \left[\begin{array}{ccc} \frac{5}{2} & \frac{1}{2} \\4&1\end{array}\right] .[/tex]

[tex]b. \star determinan P= \left[\begin{array}{ccc}3&1&2\\1&0&-2\\-5&1&3\end{array}\right] = \left|\begin{array}{ccc}3&1&2\\1&0&-2\\-5&1&3\end{array}\right| \left\begin{array}{ccc}3&1\\1&0\\-5&1\end{array}\right| kali silangkan =(3.0.3)+(1.-2.-5)+(2.1.1)-(2.0.-5)+(3.-2.1)+(1.1.3) =0+10+2+0+6-3 =15 determinannya.[/tex]