tentukan invers dari fungsi y=f(x)=√2+5x

[tex]f(x)= \sqrt{2 + 5x} \\ y= \sqrt{2 + 5x} \\ {y}^{2} = 2 + 5x \\ {y}^{2} - 2 = 5x \\ x = \frac{ {y}^{2} - 2 }{5} \\ f ^{ - 1} (x)= \frac{ {x}^{2} - 2 }{5} [/tex]